9.5多项式的因式分解(4) 1.C 2.把下列各式分解因式 (1) =x²(x²-1) =x²(x+1)(x-1) (2) =(x²-y²)(a-b) =(x+y)(x-y)(a-b) (3) =-3x²(9x²-6x+1) =-3a²(3x-1)² (4) =y²(x⁴-1) =y²(x²+1)(x²-1) =y²(x²+1)(x+1)(x-1) (5) =(a²-b²)² =[(a+b)(a-b)]² =(a+b)²(a-b)² (6) =[(a²-a)+(a-1)][(a²-a)-(a-1)] =(a²-1)(a²-2a+1) =(a+1)(a-1)(a-1)² =(a+1)(a-1)³ 3. 解:x³y-2x²y²+xy³=xy(x²-2xy+y²)=xy(x-y)² 将数值代入得: 原式=3×(-1)²=3 4. (1)填空 21 63 |